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Posted By: Andrew PalfreymanBy adding up the masses like that you seem to be ignoring the pulleys, which serve to effectively flip the sign of the end masses with respect to the beam - and we are only interested in calculating with respect to the beam. I think.
Posted By: alsetalokinI still don't see how you get a torque out of it.If d=0, there is no torque. Else (see my previous post) the torques are -3d, -2d and -d at LHS, middle and RHS resp.
Posted By: Andrew PalfreymanPosted By: alsetalokinI still don't see how you get a torque out of it.If d=0, there is no torque. Else (see my previous post) the torques are -3d, -2d and -d at LHS, middle and RHS resp.
The force on a current-carrying element of length L carrying a current I laying at right angles to a magnetic field B
Posted By: tinkerLike giant Iceverbs, drifting in the word-dark see-a.